यदि \(x^2+px+12=0\) के मूलों का अनुपात (1:3) है और दोनों ऋणात्मक हैं तो (p) क्या होगा?
If roots of \(x^2+px+12=0\) are in the ratio (1:3) and both are negative, what is (p)?
Explanation opens after your attempt
Correct Answer
A. (8)
Concept
The roots are (-2) and (-6) because the product is (12). Their sum is (-8), so (-p=-8) gives (p=8).
Why this answer is correct
The correct answer is A. (8). The roots are (-2) and (-6) because the product is (12). Their sum is (-8), so (-p=-8) gives (p=8).
Exam Tip
मूल (-2) और (-6) होंगे क्योंकि गुणनफल (12) है। उनका योग (-8) है इसलिए (-p=-8) से (p=8) है।
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