यदि (x-2-(a+1)x+a=0) के मूल (1) और (a) हैं तो यह किस कारण सही है?
If roots of (x-2-(a+1)x+a=0) are (1) and (a), why is it correct?
Explanation opens after your attempt
Correct Answer
A. योग (a+1) और गुणनफल (a) हैSum is (a+1) and product is (a)
Concept
The roots (1) and (a) have sum (a+1) and product (a). Therefore the monic equation is (x-2-(a+1)x+a=0).
Why this answer is correct
The correct answer is A. योग (a+1) और गुणनफल (a) है / Sum is (a+1) and product is (a). The roots (1) and (a) have sum (a+1) and product (a). Therefore the monic equation is (x-2-(a+1)x+a=0).
Exam Tip
मूल (1) और (a) का योग (a+1) तथा गुणनफल (a) है। इसलिए मोनिक समीकरण (x-2-(a+1)x+a=0) बनता है।
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