Hard Mathematics Polynomials Class 10 Level 25

यदि \(r=\sqrt{2}+\sqrt{3}\) है तो \(r+\frac{1}{r}\) का सरल रूप क्या है?

If \(r=\sqrt{2}+\sqrt{3}\), what is the simplified form of \(r+\frac{1}{r}\)?

Explanation opens after your attempt
Correct Answer

A. \(2\sqrt{3}\)

Step 1

Concept

\(\frac{1}{\sqrt{2}+\sqrt{3}}=\sqrt{3}-\sqrt{2}\). Adding gives \(2\sqrt{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(2\sqrt{3}\). \(\frac{1}{\sqrt{2}+\sqrt{3}}=\sqrt{3}-\sqrt{2}\). Adding gives \(2\sqrt{3}\).

Step 3

Exam Tip

\(\frac{1}{\sqrt{2}+\sqrt{3}}=\sqrt{3}-\sqrt{2}\) होता है। जोड़ने पर \(2\sqrt{3}\) मिलता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(r=\sqrt{2}+\sqrt{3}\) है तो \(r+\frac{1}{r}\) का सरल रूप क्या है? / If \(r=\sqrt{2}+\sqrt{3}\), what is the simplified form of \(r+\frac{1}{r}\)?

Correct Answer: A. \(2\sqrt{3}\). Explanation: \(\frac{1}{\sqrt{2}+\sqrt{3}}=\sqrt{3}-\sqrt{2}\) होता है। जोड़ने पर \(2\sqrt{3}\) मिलता है। / \(\frac{1}{\sqrt{2}+\sqrt{3}}=\sqrt{3}-\sqrt{2}\). Adding gives \(2\sqrt{3}\).

Which concept should I revise for this Mathematics MCQ?

\(\frac{1}{\sqrt{2}+\sqrt{3}}=\sqrt{3}-\sqrt{2}\). Adding gives \(2\sqrt{3}\).

What exam hint can help solve this Mathematics question?

\(\frac{1}{\sqrt{2}+\sqrt{3}}=\sqrt{3}-\sqrt{2}\) होता है। जोड़ने पर \(2\sqrt{3}\) मिलता है।

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