यदि (p(x)=x-2-(u+v)x+uv) है तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?
If (p(x)=x-2-(u+v)x+uv), what will be the (x)-axis intersections of the graph?
Explanation opens after your attempt
Correct Answer
A. ((u,0)) और ((v,0))((u,0)) and ((v,0))
Concept
It is ((x-u)(x-v)), so the zeroes are (u) and (v). Tip: write each zero as the point ((x,0)).
Why this answer is correct
The correct answer is A. ((u,0)) और ((v,0)) / ((u,0)) and ((v,0)). It is ((x-u)(x-v)), so the zeroes are (u) and (v). Tip: write each zero as the point ((x,0)).
Exam Tip
यह ((x-u)(x-v)) है इसलिए शून्यक (u) और (v) हैं। टिप: शून्यक को ((x,0)) बिंदु के रूप में लिखें।
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