यदि (p(x)=x-2-\(\sqrt{3}+1\)x+\sqrt{3}), तो शून्यक कौन से हैं?
If (p(x)=x-2-\(\sqrt{3}+1\)x+\sqrt{3}), what are the zeroes?
Explanation opens after your attempt
Correct Answer
A. \(1,\sqrt{3}\)
Concept
The sum is \(1+\sqrt{3}\) and the product is \(\sqrt{3}\), so the zeroes are (1) and \(\sqrt{3}\). Compare with \(x^2-Sx+P\) in exams.
Why this answer is correct
The correct answer is A. \(1,\sqrt{3}\). The sum is \(1+\sqrt{3}\) and the product is \(\sqrt{3}\), so the zeroes are (1) and \(\sqrt{3}\). Compare with \(x^2-Sx+P\) in exams.
Exam Tip
योग \(1+\sqrt{3}\) और गुणनफल \(\sqrt{3}\) है, इसलिए शून्यक (1) और \(\sqrt{3}\) हैं। परीक्षा में \(x^2-Sx+P\) से तुलना करें।
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