Expert Mathematics Polynomials Class 10 Level 27

यदि (p(x)=x-2-8x+13), तो इसके शून्यक कौन से हैं?

If (p(x)=x-2-8x+13), what are its zeroes?

Explanation opens after your attempt
Correct Answer

A. \(4+\sqrt{3}\) और \(4-\sqrt{3}\)\(4+\sqrt{3}\) and \(4-\sqrt{3}\)

Step 1

Concept

Using the quadratic formula \(x=\frac{8\pm\sqrt{64-52}}{2}=4\pm\sqrt{3}\). In exams simplify the discriminant.

Step 2

Why this answer is correct

The correct answer is A. \(4+\sqrt{3}\) और \(4-\sqrt{3}\) / \(4+\sqrt{3}\) and \(4-\sqrt{3}\). Using the quadratic formula \(x=\frac{8\pm\sqrt{64-52}}{2}=4\pm\sqrt{3}\). In exams simplify the discriminant.

Step 3

Exam Tip

द्विघात सूत्र से \(x=\frac{8\pm\sqrt{64-52}}{2}=4\pm\sqrt{3}\) मिलता है। परीक्षा में विविक्तकर को सरल करें।

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2-8x+13), तो इसके शून्यक कौन से हैं? / If (p(x)=x-2-8x+13), what are its zeroes?

Correct Answer: A. \(4+\sqrt{3}\) और \(4-\sqrt{3}\) / \(4+\sqrt{3}\) and \(4-\sqrt{3}\). Explanation: द्विघात सूत्र से \(x=\frac{8\pm\sqrt{64-52}}{2}=4\pm\sqrt{3}\) मिलता है। परीक्षा में विविक्तकर को सरल करें। / Using the quadratic formula \(x=\frac{8\pm\sqrt{64-52}}{2}=4\pm\sqrt{3}\). In exams simplify the discriminant.

Which concept should I revise for this Mathematics MCQ?

Using the quadratic formula \(x=\frac{8\pm\sqrt{64-52}}{2}=4\pm\sqrt{3}\). In exams simplify the discriminant.

What exam hint can help solve this Mathematics question?

द्विघात सूत्र से \(x=\frac{8\pm\sqrt{64-52}}{2}=4\pm\sqrt{3}\) मिलता है। परीक्षा में विविक्तकर को सरल करें।

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