Hard Mathematics Polynomials Class 10 Level 27

यदि (p(x)=x-2-3x-\sqrt{2}) है, तो (p(x)) के गुणांकों के बारे में सही कथन कौन सा है?

If (p(x)=x-2-3x-\sqrt{2}), which statement about the coefficients of (p(x)) is correct?

Explanation opens after your attempt
Correct Answer

B. एक गुणांक अपरिमेय हैOne coefficient is irrational

Step 1

Concept

The constant term \(-\sqrt{2}\) is irrational, while the other coefficients are rational. Check coefficient type before applying root rules.

Step 2

Why this answer is correct

The correct answer is B. एक गुणांक अपरिमेय है / One coefficient is irrational. The constant term \(-\sqrt{2}\) is irrational, while the other coefficients are rational. Check coefficient type before applying root rules.

Step 3

Exam Tip

स्थिर पद \(-\sqrt{2}\) अपरिमेय है, जबकि बाकी गुणांक परिमेय हैं। शून्यक नियम लागू करने से पहले गुणांकों का प्रकार देखें।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2-3x-\sqrt{2}) है, तो (p(x)) के गुणांकों के बारे में सही कथन कौन सा है? / If (p(x)=x-2-3x-\sqrt{2}), which statement about the coefficients of (p(x)) is correct?

Correct Answer: B. एक गुणांक अपरिमेय है / One coefficient is irrational. Explanation: स्थिर पद \(-\sqrt{2}\) अपरिमेय है, जबकि बाकी गुणांक परिमेय हैं। शून्यक नियम लागू करने से पहले गुणांकों का प्रकार देखें। / The constant term \(-\sqrt{2}\) is irrational, while the other coefficients are rational. Check coefficient type before applying root rules.

Which concept should I revise for this Mathematics MCQ?

The constant term \(-\sqrt{2}\) is irrational, while the other coefficients are rational. Check coefficient type before applying root rules.

What exam hint can help solve this Mathematics question?

स्थिर पद \(-\sqrt{2}\) अपरिमेय है, जबकि बाकी गुणांक परिमेय हैं। शून्यक नियम लागू करने से पहले गुणांकों का प्रकार देखें।

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