Hard Mathematics Polynomials Class 10 Level 27

यदि (p(x)=x-2-2) है, तो (p(x)) के शून्यकों के बारे में सही कथन कौन सा है?

If (p(x)=x-2-2), which statement about the zeroes of (p(x)) is correct?

Explanation opens after your attempt
Correct Answer

B. दोनों अपरिमेय वास्तविक हैंBoth are irrational real

Step 1

Concept

From \(x^2-2=0\), \(x=\pm\sqrt{2}\), which are irrational real numbers. In exams, check both real nature and rationality of roots.

Step 2

Why this answer is correct

The correct answer is B. दोनों अपरिमेय वास्तविक हैं / Both are irrational real. From \(x^2-2=0\), \(x=\pm\sqrt{2}\), which are irrational real numbers. In exams, check both real nature and rationality of roots.

Step 3

Exam Tip

\(x^2-2=0\) से \(x=\pm\sqrt{2}\), जो अपरिमेय वास्तविक संख्याएँ हैं। परीक्षा में मूल निकालते समय वास्तविकता और परिमेयता दोनों जाँचें।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2-2) है, तो (p(x)) के शून्यकों के बारे में सही कथन कौन सा है? / If (p(x)=x-2-2), which statement about the zeroes of (p(x)) is correct?

Correct Answer: B. दोनों अपरिमेय वास्तविक हैं / Both are irrational real. Explanation: \(x^2-2=0\) से \(x=\pm\sqrt{2}\), जो अपरिमेय वास्तविक संख्याएँ हैं। परीक्षा में मूल निकालते समय वास्तविकता और परिमेयता दोनों जाँचें। / From \(x^2-2=0\), \(x=\pm\sqrt{2}\), which are irrational real numbers. In exams, check both real nature and rationality of roots.

Which concept should I revise for this Mathematics MCQ?

From \(x^2-2=0\), \(x=\pm\sqrt{2}\), which are irrational real numbers. In exams, check both real nature and rationality of roots.

What exam hint can help solve this Mathematics question?

\(x^2-2=0\) से \(x=\pm\sqrt{2}\), जो अपरिमेय वास्तविक संख्याएँ हैं। परीक्षा में मूल निकालते समय वास्तविकता और परिमेयता दोनों जाँचें।

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