यदि (p(x)=x-2-2\sqrt{2}x+1) है, तो शून्यकों का प्रकार क्या है?
If (p(x)=x-2-2\sqrt{2}x+1), what is the type of its zeroes?
Explanation opens after your attempt
Correct Answer
A. दो भिन्न वास्तविक अपरिमेयTwo distinct real irrational
Concept
(D=\(2\sqrt{2}\)2-4=8-4=4), and the zeroes are \(\sqrt{2}\pm1\). They are real and irrational.
Why this answer is correct
The correct answer is A. दो भिन्न वास्तविक अपरिमेय / Two distinct real irrational. (D=\(2\sqrt{2}\)2-4=8-4=4), and the zeroes are \(\sqrt{2}\pm1\). They are real and irrational.
Exam Tip
(D=\(2\sqrt{2}\)2-4=8-4=4) है और शून्यक \(\sqrt{2}\pm1\) हैं। ये वास्तविक और अपरिमेय हैं।
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