यदि (p(x)=5(x+2)2(x-7)) है, तो ग्राफ कितने अलग बिंदुओं पर (x)-अक्ष से मिलेगा और कौन सा बिंदु स्पर्श होगा?
If (p(x)=5(x+2)2(x-7)), at how many distinct points will the graph meet the (x)-axis and which point will be a touching point?
Explanation opens after your attempt
A. दो बिंदु, (x=-2) पर स्पर्शTwo points, touching at (x=-2)
Concept
The zeroes are (-2) and (7), and ((x+2)2) causes touching at (-2). Tip: the outside (5) does not change the zeroes.
Why this answer is correct
The correct answer is A. दो बिंदु, (x=-2) पर स्पर्श / Two points, touching at (x=-2). The zeroes are (-2) and (7), and ((x+2)2) causes touching at (-2). Tip: the outside (5) does not change the zeroes.
Exam Tip
शून्यक (-2) और (7) हैं, तथा ((x+2)2) के कारण (-2) पर स्पर्श है। टिप: बाहरी (5) शून्यक नहीं बदलता।
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