यदि (p(x)=11(x+5)2(x-14)) है, तो ग्राफ कितने अलग बिंदुओं पर (x)-अक्ष से मिलेगा और कौन सा बिंदु स्पर्श होगा?
If (p(x)=11(x+5)2(x-14)), at how many distinct points will the graph meet the (x)-axis and which point will be a touching point?
Explanation opens after your attempt
A. दो बिंदु, (x=-5) पर स्पर्शTwo points, touching at (x=-5)
Concept
The zeroes are (-5) and (14), and ((x+5)2) causes touching at (-5). Tip: the outside (11) does not change the zeroes.
Why this answer is correct
The correct answer is A. दो बिंदु, (x=-5) पर स्पर्श / Two points, touching at (x=-5). The zeroes are (-5) and (14), and ((x+5)2) causes touching at (-5). Tip: the outside (11) does not change the zeroes.
Exam Tip
शून्यक (-5) और (14) हैं तथा ((x+5)2) के कारण (-5) पर स्पर्श है। टिप: बाहरी (11) शून्यक नहीं बदलता।
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