यदि (p) और (q) शून्येतर परिमेय संख्याएं हैं और \(p+q\sqrt{2}=0\), तो कौन सा निष्कर्ष सही है?
If (p) and (q) are non-zero rational numbers and \(p+q\sqrt{2}=0\), which conclusion is correct?
Explanation opens after your attempt
A. \(\sqrt{2}=-\frac{p}{q}\), इसलिए \(\sqrt{2}\) परिमेय होगा जो असंभव है\(\sqrt{2}=-\frac{p}{q}\), so \(\sqrt{2}\) would be rational which is impossible
Concept
Since \(-\frac{p}{q}\) is rational, this would make \(\sqrt{2}\) rational which is false. In exams recognize the contradiction method.
Why this answer is correct
The correct answer is A. \(\sqrt{2}=-\frac{p}{q}\), इसलिए \(\sqrt{2}\) परिमेय होगा जो असंभव है / \(\sqrt{2}=-\frac{p}{q}\), so \(\sqrt{2}\) would be rational which is impossible. Since \(-\frac{p}{q}\) is rational, this would make \(\sqrt{2}\) rational which is false. In exams recognize the contradiction method.
Exam Tip
क्योंकि \(-\frac{p}{q}\) परिमेय है, इससे \(\sqrt{2}\) परिमेय मानना पड़ेगा जो गलत है। परीक्षा में विरोधाभास विधि को पहचानें।
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