यदि (p(-3)=0), (p(0)=5) और (p(4)=0), तो ग्राफ (x)-अक्ष को किन बिंदुओं पर काटेगा?
If (p(-3)=0), (p(0)=5) and (p(4)=0), at which points will the graph cut the (x)-axis?
Explanation opens after your attempt
B. ((-3,0)) और ((4,0))((-3,0)) and ((4,0))
Concept
Where (p(x)=0), there is an (x)-axis intersection. Tip: (p(0)=5) does not give a zero.
Why this answer is correct
The correct answer is B. ((-3,0)) और ((4,0)) / ((-3,0)) and ((4,0)). Where (p(x)=0), there is an (x)-axis intersection. Tip: (p(0)=5) does not give a zero.
Exam Tip
जहाँ (p(x)=0) है वहीं (x)-अक्ष कटान है। टिप: (p(0)=5) शून्यक नहीं देता।
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