Hard Mathematics Polynomials Class 10 Level 25

यदि \(p=2+\sqrt{3}\) है तो \(\frac{1}{p}\) किसके बराबर है?

If \(p=2+\sqrt{3}\), what is \(\frac{1}{p}\) equal to?

Explanation opens after your attempt
Correct Answer

A. \(2-\sqrt{3}\)

Step 1

Concept

Since (\(2+\sqrt{3}\)\(2-\sqrt{3}\)=1), the reciprocal is \(2-\sqrt{3}\). Recognizing conjugates is a fast method.

Step 2

Why this answer is correct

The correct answer is A. \(2-\sqrt{3}\). Since (\(2+\sqrt{3}\)\(2-\sqrt{3}\)=1), the reciprocal is \(2-\sqrt{3}\). Recognizing conjugates is a fast method.

Step 3

Exam Tip

क्योंकि (\(2+\sqrt{3}\)\(2-\sqrt{3}\)=1), इसलिए व्युत्क्रम \(2-\sqrt{3}\) है। संयुग्मी को पहचानना तेज तरीका है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(p=2+\sqrt{3}\) है तो \(\frac{1}{p}\) किसके बराबर है? / If \(p=2+\sqrt{3}\), what is \(\frac{1}{p}\) equal to?

Correct Answer: A. \(2-\sqrt{3}\). Explanation: क्योंकि (\(2+\sqrt{3}\)\(2-\sqrt{3}\)=1), इसलिए व्युत्क्रम \(2-\sqrt{3}\) है। संयुग्मी को पहचानना तेज तरीका है। / Since (\(2+\sqrt{3}\)\(2-\sqrt{3}\)=1), the reciprocal is \(2-\sqrt{3}\). Recognizing conjugates is a fast method.

Which concept should I revise for this Mathematics MCQ?

Since (\(2+\sqrt{3}\)\(2-\sqrt{3}\)=1), the reciprocal is \(2-\sqrt{3}\). Recognizing conjugates is a fast method.

What exam hint can help solve this Mathematics question?

क्योंकि (\(2+\sqrt{3}\)\(2-\sqrt{3}\)=1), इसलिए व्युत्क्रम \(2-\sqrt{3}\) है। संयुग्मी को पहचानना तेज तरीका है।

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