यदि \(x^2-21x+q=0\) का एक मूल (8) है, तो (q) का मान क्या होगा?
If one root of \(x^2-21x+q=0\) is (8), what is the value of (q)?
Explanation opens after your attempt
A. (104)
Concept
The other root is (13), so \(q=8\times13=104\). In exams, when (a=1), the constant term is the product of roots.
Why this answer is correct
The correct answer is A. (104). The other root is (13), so \(q=8\times13=104\). In exams, when (a=1), the constant term is the product of roots.
Exam Tip
दूसरा मूल (13) है, इसलिए \(q=8\times13=104\) होगा। परीक्षा में (a=1) हो तो स्थिर पद मूलों का गुणनफल होता है।
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