Hard Mathematics Quadratic Equations Class 10 Level 36

यदि \(kx^2-14x+49=0\) के समान मूल हैं, तो (k) क्या होगा?

If \(kx^2-14x+49=0\) has equal roots, what is (k)?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

For equal roots, (D=0), so (196-196k=0) and (k=1). In exams, keep (a=k) correctly.

Step 2

Why this answer is correct

The correct answer is A. (1). For equal roots, (D=0), so (196-196k=0) and (k=1). In exams, keep (a=k) correctly.

Step 3

Exam Tip

समान मूलों के लिए (D=0), इसलिए (196-196k=0) और (k=1) है। परीक्षा में (a=k) को ठीक से रखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(kx^2-14x+49=0\) के समान मूल हैं, तो (k) क्या होगा? / If \(kx^2-14x+49=0\) has equal roots, what is (k)?

Correct Answer: A. (1). Explanation: समान मूलों के लिए (D=0), इसलिए (196-196k=0) और (k=1) है। परीक्षा में (a=k) को ठीक से रखें। / For equal roots, (D=0), so (196-196k=0) and (k=1). In exams, keep (a=k) correctly.

Which concept should I revise for this Mathematics MCQ?

For equal roots, (D=0), so (196-196k=0) and (k=1). In exams, keep (a=k) correctly.

What exam hint can help solve this Mathematics question?

समान मूलों के लिए (D=0), इसलिए (196-196k=0) और (k=1) है। परीक्षा में (a=k) को ठीक से रखें।

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