Expert Mathematics Polynomials Class 10 Level 26

यदि \(\frac{1}{\sqrt{7}+\sqrt{6}}\) को परिमेयकृत किया जाए, तो मान क्या होगा?

If \(\frac{1}{\sqrt{7}+\sqrt{6}}\) is rationalized, what is its value?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{7}-\sqrt{6}\)

Step 1

Concept

The conjugate of the denominator is \(\sqrt{7}-\sqrt{6}\), and the denominator becomes (7-6=1). In exams the answer simplifies when the difference is (1).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{7}-\sqrt{6}\). The conjugate of the denominator is \(\sqrt{7}-\sqrt{6}\), and the denominator becomes (7-6=1). In exams the answer simplifies when the difference is (1).

Step 3

Exam Tip

हर का संयुग्मी \(\sqrt{7}-\sqrt{6}\) है और हर (7-6=1) बनता है। परीक्षा में अंतर (1) होने पर उत्तर सरल हो जाता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\frac{1}{\sqrt{7}+\sqrt{6}}\) को परिमेयकृत किया जाए, तो मान क्या होगा? / If \(\frac{1}{\sqrt{7}+\sqrt{6}}\) is rationalized, what is its value?

Correct Answer: A. \(\sqrt{7}-\sqrt{6}\). Explanation: हर का संयुग्मी \(\sqrt{7}-\sqrt{6}\) है और हर (7-6=1) बनता है। परीक्षा में अंतर (1) होने पर उत्तर सरल हो जाता है। / The conjugate of the denominator is \(\sqrt{7}-\sqrt{6}\), and the denominator becomes (7-6=1). In exams the answer simplifies when the difference is (1).

Which concept should I revise for this Mathematics MCQ?

The conjugate of the denominator is \(\sqrt{7}-\sqrt{6}\), and the denominator becomes (7-6=1). In exams the answer simplifies when the difference is (1).

What exam hint can help solve this Mathematics question?

हर का संयुग्मी \(\sqrt{7}-\sqrt{6}\) है और हर (7-6=1) बनता है। परीक्षा में अंतर (1) होने पर उत्तर सरल हो जाता है।

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