Expert Mathematics Relations and Functions Class 12 Level 21

यदि (f(x)=\frac{1}{x+1}) हो तो (\(f\circ f\)(x)) क्या होगा?

If (f(x)=\frac{1}{x+1}), what is (\(f\circ f\)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\frac{x+1}{x+2}\)

Step 1

Concept

(\(f\circ f\)(x)=f(f(x))).

Step 2

Why this answer is correct

(f(f(x))=\frac{1}{\frac{1}{x+1}+1}=\frac{x+1}{x+2}).

Step 3

Exam Tip

In fractional compositions, simplify the denominator carefully. चरण 1: (\(f\circ f\)(x)=f(f(x))) है। चरण 2: (f(f(x))=\frac{1}{\frac{1}{x+1}+1}=\frac{x+1}{x+2})। चरण 3: भिन्न वाले समिश्र फलनों में हर को सावधानी से सरल करें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{1}{x+1}) हो तो (\(f\circ f\)(x)) क्या होगा? / If (f(x)=\frac{1}{x+1}), what is (\(f\circ f\)(x))?

Correct Answer: A. \(\frac{x+1}{x+2}\). Explanation: चरण 1: (\(f\circ f\)(x)=f(f(x))) है। चरण 2: (f(f(x))=\frac{1}{\frac{1}{x+1}+1}=\frac{x+1}{x+2})। चरण 3: भिन्न वाले समिश्र फलनों में हर को सावधानी से सरल करें। / Step 1: (\(f\circ f\)(x)=f(f(x))). Step 2: (f(f(x))=\frac{1}{\frac{1}{x+1}+1}=\frac{x+1}{x+2}). Step 3: In fractional compositions, simplify the denominator carefully.

Which concept should I revise for this Mathematics MCQ?

(\(f\circ f\)(x)=f(f(x))).

What exam hint can help solve this Mathematics question?

In fractional compositions, simplify the denominator carefully. चरण 1: (\(f\circ f\)(x)=f(f(x))) है। चरण 2: (f(f(x))=\frac{1}{\frac{1}{x+1}+1}=\frac{x+1}{x+2})। चरण 3: भिन्न वाले समिश्र फलनों में हर को सावधानी से सरल करें।

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