Hard Mathematics Polynomials Class 10 Level 26

यदि \(\alpha=\sqrt{12}\) और \(\beta=-\sqrt{3}\), तो \(\alpha+\beta\) क्या है?

If \(\alpha=\sqrt{12}\) and \(\beta=-\sqrt{3}\), what is \(\alpha+\beta\)?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{3}\)

Step 1

Concept

\(\sqrt{12}=2\sqrt{3}\), so \(\alpha+\beta=2\sqrt{3}-\sqrt{3}=\sqrt{3}\). Simplifying radicals is important.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{3}\). \(\sqrt{12}=2\sqrt{3}\), so \(\alpha+\beta=2\sqrt{3}-\sqrt{3}=\sqrt{3}\). Simplifying radicals is important.

Step 3

Exam Tip

\(\sqrt{12}=2\sqrt{3}\), इसलिए \(\alpha+\beta=2\sqrt{3}-\sqrt{3}=\sqrt{3}\)। करणी सरल करना जरूरी है।

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(\alpha=\sqrt{12}\) और \(\beta=-\sqrt{3}\), तो \(\alpha+\beta\) क्या है? / If \(\alpha=\sqrt{12}\) and \(\beta=-\sqrt{3}\), what is \(\alpha+\beta\)?

Correct Answer: A. \(\sqrt{3}\). Explanation: \(\sqrt{12}=2\sqrt{3}\), इसलिए \(\alpha+\beta=2\sqrt{3}-\sqrt{3}=\sqrt{3}\)। करणी सरल करना जरूरी है। / \(\sqrt{12}=2\sqrt{3}\), so \(\alpha+\beta=2\sqrt{3}-\sqrt{3}=\sqrt{3}\). Simplifying radicals is important.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{12}=2\sqrt{3}\), so \(\alpha+\beta=2\sqrt{3}-\sqrt{3}=\sqrt{3}\). Simplifying radicals is important.

What exam hint can help solve this Mathematics question?

\(\sqrt{12}=2\sqrt{3}\), इसलिए \(\alpha+\beta=2\sqrt{3}-\sqrt{3}=\sqrt{3}\)। करणी सरल करना जरूरी है।

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