Hard Mathematics Quadratic Equations Class 10 Level 32

यदि \(x^2-6x+5=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\alpha+3\) और \(\beta+3\) का योग क्या होगा?

If \(\alpha\) and \(\beta\) are roots of \(x^2-6x+5=0\), what is the sum of \(\alpha+3\) and \(\beta+3\)?

Explanation opens after your attempt
Correct Answer

A. (12)

Step 1

Concept

The old sum of roots is (6). The new sum is (\(\alpha+3\)+\(\beta+3\)=6+6=12).

Step 2

Why this answer is correct

The correct answer is A. (12). The old sum of roots is (6). The new sum is (\(\alpha+3\)+\(\beta+3\)=6+6=12).

Step 3

Exam Tip

पुराने मूलों का योग (6) है। नया योग (\(\alpha+3\)+\(\beta+3\)=6+6=12) होगा।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-6x+5=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\alpha+3\) और \(\beta+3\) का योग क्या होगा? / If \(\alpha\) and \(\beta\) are roots of \(x^2-6x+5=0\), what is the sum of \(\alpha+3\) and \(\beta+3\)?

Correct Answer: A. (12). Explanation: पुराने मूलों का योग (6) है। नया योग (\(\alpha+3\)+\(\beta+3\)=6+6=12) होगा। / The old sum of roots is (6). The new sum is (\(\alpha+3\)+\(\beta+3\)=6+6=12).

Which concept should I revise for this Mathematics MCQ?

The old sum of roots is (6). The new sum is (\(\alpha+3\)+\(\beta+3\)=6+6=12).

What exam hint can help solve this Mathematics question?

पुराने मूलों का योग (6) है। नया योग (\(\alpha+3\)+\(\beta+3\)=6+6=12) होगा।

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