Expert Mathematics Polynomials Class 10 Level 27

यदि \(\alpha=7+\sqrt{6}\) और \(\beta=7-\sqrt{6}\), तो \(\alpha^2+\beta^2\) क्या है?

If \(\alpha=7+\sqrt{6}\) and \(\beta=7-\sqrt{6}\), what is \(\alpha^2+\beta^2\)?

Explanation opens after your attempt
Correct Answer

A. (110)

Step 1

Concept

\(\alpha+\beta=14\) and \(\alpha\beta=43\) so (\alpha-2+\beta-2=(14)2-2(43)=110). In exams use (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta).

Step 2

Why this answer is correct

The correct answer is A. (110). \(\alpha+\beta=14\) and \(\alpha\beta=43\) so (\alpha-2+\beta-2=(14)2-2(43)=110). In exams use (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta).

Step 3

Exam Tip

\(\alpha+\beta=14\) और \(\alpha\beta=43\) है इसलिए (\alpha-2+\beta-2=(14)2-2(43)=110)। परीक्षा में पहचान (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) लगाएं।

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(\alpha=7+\sqrt{6}\) और \(\beta=7-\sqrt{6}\), तो \(\alpha^2+\beta^2\) क्या है? / If \(\alpha=7+\sqrt{6}\) and \(\beta=7-\sqrt{6}\), what is \(\alpha^2+\beta^2\)?

Correct Answer: A. (110). Explanation: \(\alpha+\beta=14\) और \(\alpha\beta=43\) है इसलिए (\alpha-2+\beta-2=(14)2-2(43)=110)। परीक्षा में पहचान (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) लगाएं। / \(\alpha+\beta=14\) and \(\alpha\beta=43\) so (\alpha-2+\beta-2=(14)2-2(43)=110). In exams use (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta).

Which concept should I revise for this Mathematics MCQ?

\(\alpha+\beta=14\) and \(\alpha\beta=43\) so (\alpha-2+\beta-2=(14)2-2(43)=110). In exams use (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta).

What exam hint can help solve this Mathematics question?

\(\alpha+\beta=14\) और \(\alpha\beta=43\) है इसलिए (\alpha-2+\beta-2=(14)2-2(43)=110)। परीक्षा में पहचान (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) लगाएं।

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