यदि \(\alpha=5+\sqrt{6}\) और \(\beta=5-\sqrt{6}\), तो \(\alpha^2+\beta^2\) का मान क्या है?
If \(\alpha=5+\sqrt{6}\) and \(\beta=5-\sqrt{6}\), what is the value of \(\alpha^2+\beta^2\)?
Explanation opens after your attempt
Correct Answer
A. (62)
Concept
\(\alpha+\beta=10\) and \(\alpha\beta=25-6=19\), so \(\alpha^2+\beta^2=100-38=62\). Use (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta).
Why this answer is correct
The correct answer is A. (62). \(\alpha+\beta=10\) and \(\alpha\beta=25-6=19\), so \(\alpha^2+\beta^2=100-38=62\). Use (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta).
Exam Tip
\(\alpha+\beta=10\) और \(\alpha\beta=25-6=19\), इसलिए \(\alpha^2+\beta^2=100-38=62\)। पहचान (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) उपयोग करें।
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