Hard Mathematics Sets Class 11 Level 7

यदि \(A={x:x\) (18) का धनात्मक भाजक है और (x) विषम है(}) तो कौन सा समुच्चय (A) के बराबर है?

If \(A={x:x\) is a positive divisor of (18) and (x) is odd(}), which set is equal to (A)?

Explanation opens after your attempt
Correct Answer

A. ({1,3,9})

Step 1

Concept

The odd positive divisors of (18) are (1,3,9). Apply all conditions together.

Step 2

Why this answer is correct

The correct answer is A. ({1,3,9}). The odd positive divisors of (18) are (1,3,9). Apply all conditions together.

Step 3

Exam Tip

(18) के विषम धनात्मक भाजक (1,3,9) हैं। सभी शर्तों को साथ में लागू करें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x\) (18) का धनात्मक भाजक है और (x) विषम है(}) तो कौन सा समुच्चय (A) के बराबर है? / If \(A={x:x\) is a positive divisor of (18) and (x) is odd(}), which set is equal to (A)?

Correct Answer: A. ({1,3,9}). Explanation: (18) के विषम धनात्मक भाजक (1,3,9) हैं। सभी शर्तों को साथ में लागू करें। / The odd positive divisors of (18) are (1,3,9). Apply all conditions together.

Which concept should I revise for this Mathematics MCQ?

The odd positive divisors of (18) are (1,3,9). Apply all conditions together.

What exam hint can help solve this Mathematics question?

(18) के विषम धनात्मक भाजक (1,3,9) हैं। सभी शर्तों को साथ में लागू करें।

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