यदि \(A={x:x\) (18) का धनात्मक भाजक है और (x) विषम है(}) तो कौन सा समुच्चय (A) के बराबर है?
If \(A={x:x\) is a positive divisor of (18) and (x) is odd(}), which set is equal to (A)?
Explanation opens after your attempt
A. ({1,3,9})
Concept
The odd positive divisors of (18) are (1,3,9). Apply all conditions together.
Why this answer is correct
The correct answer is A. ({1,3,9}). The odd positive divisors of (18) are (1,3,9). Apply all conditions together.
Exam Tip
(18) के विषम धनात्मक भाजक (1,3,9) हैं। सभी शर्तों को साथ में लागू करें।
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