Expert Mathematics Sets Class 11 Level 7

यदि \(A={x:x}\in Z\) और |x-2|<2 तथा B={1,2,3} हैं तो कौन सा कथन सही है?

If A={x:x∈Z and ∣x−2∣<2} and B={1,2,3}, then which statement is correct?

Explanation opens after your attempt
Correct Answer

A. (A=B)

Step 1

Concept

The inequality (|x-2|<2) gives integer values (1,2,3), so the sets are equal. In exams solve the inequality first and write roster form.

Step 2

Why this answer is correct

The correct answer is A. (A=B). The inequality (|x-2|<2) gives integer values (1,2,3), so the sets are equal. In exams solve the inequality first and write roster form.

Step 3

Exam Tip

(|x-2|<2) से पूर्णांक मान (1,2,3) मिलते हैं इसलिए दोनों समुच्चय बराबर हैं। परीक्षा में असमता को पहले हल करके रोस्टर रूप लिखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x}\in Z\) और |x-2|<2 तथा B={1,2,3} हैं तो कौन सा कथन सही है? / If A={x:x∈Z and ∣x−2∣<2} and B={1,2,3}, then which statement is correct?

Correct Answer: A. (A=B). Explanation: (|x-2|<2) से पूर्णांक मान (1,2,3) मिलते हैं इसलिए दोनों समुच्चय बराबर हैं। परीक्षा में असमता को पहले हल करके रोस्टर रूप लिखें। / The inequality (|x-2|<2) gives integer values (1,2,3), so the sets are equal. In exams solve the inequality first and write roster form.

Which concept should I revise for this Mathematics MCQ?

The inequality (|x-2|<2) gives integer values (1,2,3), so the sets are equal. In exams solve the inequality first and write roster form.

What exam hint can help solve this Mathematics question?

(|x-2|<2) से पूर्णांक मान (1,2,3) मिलते हैं इसलिए दोनों समुच्चय बराबर हैं। परीक्षा में असमता को पहले हल करके रोस्टर रूप लिखें।

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