यदि \(a=\sqrt{8}+\sqrt{18}\) है तो (a) का वर्ग किस प्रकार की संख्या है?
If \(a=\sqrt{8}+\sqrt{18}\), what type of number is \(a^2\)?
Explanation opens after your attempt
Correct Answer
A. परिमेय संख्याRational number
Concept
\(\sqrt{8}=2\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\), so \(a=5\sqrt{2}\). Its square is (50), a rational number.
Why this answer is correct
The correct answer is A. परिमेय संख्या / Rational number. \(\sqrt{8}=2\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\), so \(a=5\sqrt{2}\). Its square is (50), a rational number.
Exam Tip
\(\sqrt{8}=2\sqrt{2}\) और \(\sqrt{18}=3\sqrt{2}\), इसलिए \(a=5\sqrt{2}\)। इसका वर्ग (50) परिमेय है।
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