यदि \(a=\sqrt{11}+\sqrt{5}\) और \(b=\sqrt{11}-\sqrt{5}\), तो (ab) क्या होगा?
If \(a=\sqrt{11}+\sqrt{5}\) and \(b=\sqrt{11}-\sqrt{5}\), what is (ab)?
Explanation opens after your attempt
A. (6)
Concept
(ab=\(\sqrt{11}\)2-\(\sqrt{5}\)2=11-5=6). In exams conjugate multiplication removes radicals.
Why this answer is correct
The correct answer is A. (6). (ab=\(\sqrt{11}\)2-\(\sqrt{5}\)2=11-5=6). In exams conjugate multiplication removes radicals.
Exam Tip
(ab=\(\sqrt{11}\)2-\(\sqrt{5}\)2=11-5=6) है। परीक्षा में संयुग्मी गुणन से मूल हट जाते हैं।
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