Easy Mathematics Quadratic Equations Class 10 Level 31

समीकरण \(x^2+4=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+4=0\) have?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

Because \(x^2\ge 0\) so \(x^2+4\) never becomes (0). Therefore it has no real root.

Step 2

Why this answer is correct

The correct answer is C. (0). Because \(x^2\ge 0\) so \(x^2+4\) never becomes (0). Therefore it has no real root.

Step 3

Exam Tip

क्योंकि \(x^2\ge 0\) होता है इसलिए \(x^2+4\) कभी (0) नहीं बनता। इसलिए कोई वास्तविक मूल नहीं है।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(x^2+4=0\) के वास्तविक मूलों की संख्या कितनी है? / How many real roots does \(x^2+4=0\) have?

Correct Answer: C. (0). Explanation: क्योंकि \(x^2\ge 0\) होता है इसलिए \(x^2+4\) कभी (0) नहीं बनता। इसलिए कोई वास्तविक मूल नहीं है। / Because \(x^2\ge 0\) so \(x^2+4\) never becomes (0). Therefore it has no real root.

Which concept should I revise for this Mathematics MCQ?

Because \(x^2\ge 0\) so \(x^2+4\) never becomes (0). Therefore it has no real root.

What exam hint can help solve this Mathematics question?

क्योंकि \(x^2\ge 0\) होता है इसलिए \(x^2+4\) कभी (0) नहीं बनता। इसलिए कोई वास्तविक मूल नहीं है।

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