Hard Mathematics Quadratic Equations Class 10 Level 31

समीकरण \(x^2+2x+5=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+2x+5=0\) have?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Here (D=4-20=-16<0). Therefore the number of real roots is (0).

Step 2

Why this answer is correct

The correct answer is A. (0). Here (D=4-20=-16<0). Therefore the number of real roots is (0).

Step 3

Exam Tip

यहां (D=4-20=-16<0) है। इसलिए वास्तविक मूलों की संख्या (0) है।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(x^2+2x+5=0\) के वास्तविक मूलों की संख्या कितनी है? / How many real roots does \(x^2+2x+5=0\) have?

Correct Answer: A. (0). Explanation: यहां (D=4-20=-16<0) है। इसलिए वास्तविक मूलों की संख्या (0) है। / Here (D=4-20=-16<0). Therefore the number of real roots is (0).

Which concept should I revise for this Mathematics MCQ?

Here (D=4-20=-16<0). Therefore the number of real roots is (0).

What exam hint can help solve this Mathematics question?

यहां (D=4-20=-16<0) है। इसलिए वास्तविक मूलों की संख्या (0) है।

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