\(x^2-16=0\) को गुणनखंड रूप में कैसे लिखेंगे?
How do we write \(x^2-16=0\) in factor form?
Explanation opens after your attempt
A. \((x-4)(x+4)=0\)
Concept
\(x^2-16\) is a difference of squares. Hence it becomes ((x-4)(x+4)).
Why this answer is correct
The correct answer is A. \((x-4)(x+4)=0\). \(x^2-16\) is a difference of squares. Hence it becomes ((x-4)(x+4)).
Exam Tip
\(x^2-16\) वर्गों का अंतर है। इसलिए यह ((x-4)(x+4)) बनता है।
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