\(\frac{1}{x}+x=\frac{17}{4}\), \(x\neq0\), को द्विघात रूप में बदलने पर क्या मिलेगा?
For \(\frac{1}{x}+x=\frac{17}{4}\), \(x\neq0\), what quadratic form is obtained?
Explanation opens after your attempt
Correct Answer
A. \(4x^2-17x+4=0\)
Concept
Multiplying both sides by (4x) gives \(4+4x^2=17x\), that is \(4x^2-17x+4=0\). In exams, remember the condition \(x\neq0\).
Why this answer is correct
The correct answer is A. \(4x^2-17x+4=0\). Multiplying both sides by (4x) gives \(4+4x^2=17x\), that is \(4x^2-17x+4=0\). In exams, remember the condition \(x\neq0\).
Exam Tip
दोनों पक्षों को (4x) से गुणा करने पर \(4+4x^2=17x\), यानी \(4x^2-17x+4=0\) मिलता है। परीक्षा में \(x\neq0\) शर्त याद रखें।
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