Hard Mathematics Quadratic Equations Class 10 Level 35

\(\frac{1}{x}+x=\frac{10}{3}\), \(x\neq0\), को द्विघात रूप में बदलने पर क्या मिलेगा?

For \(\frac{1}{x}+x=\frac{10}{3}\), \(x\neq0\), what quadratic form is obtained?

Explanation opens after your attempt
Correct Answer

A. \(3x^2-10x+3=0\)

Step 1

Concept

Multiplying both sides by (3x) gives \(3+3x^2=10x\), that is \(3x^2-10x+3=0\). In exams, remember the condition \(x\neq0\).

Step 2

Why this answer is correct

The correct answer is A. \(3x^2-10x+3=0\). Multiplying both sides by (3x) gives \(3+3x^2=10x\), that is \(3x^2-10x+3=0\). In exams, remember the condition \(x\neq0\).

Step 3

Exam Tip

दोनों पक्षों को (3x) से गुणा करने पर \(3+3x^2=10x\), यानी \(3x^2-10x+3=0\) मिलता है। परीक्षा में \(x\neq0\) शर्त याद रखें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\frac{1}{x}+x=\frac{10}{3}\), \(x\neq0\), को द्विघात रूप में बदलने पर क्या मिलेगा? / For \(\frac{1}{x}+x=\frac{10}{3}\), \(x\neq0\), what quadratic form is obtained?

Correct Answer: A. \(3x^2-10x+3=0\). Explanation: दोनों पक्षों को (3x) से गुणा करने पर \(3+3x^2=10x\), यानी \(3x^2-10x+3=0\) मिलता है। परीक्षा में \(x\neq0\) शर्त याद रखें। / Multiplying both sides by (3x) gives \(3+3x^2=10x\), that is \(3x^2-10x+3=0\). In exams, remember the condition \(x\neq0\).

Which concept should I revise for this Mathematics MCQ?

Multiplying both sides by (3x) gives \(3+3x^2=10x\), that is \(3x^2-10x+3=0\). In exams, remember the condition \(x\neq0\).

What exam hint can help solve this Mathematics question?

दोनों पक्षों को (3x) से गुणा करने पर \(3+3x^2=10x\), यानी \(3x^2-10x+3=0\) मिलता है। परीक्षा में \(x\neq0\) शर्त याद रखें।

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