समीकरण \(2x^2+3x+\lambda=0\) के वास्तविक और असमान मूलों के लिए कौन सी शर्त सही है?
For \(2x^2+3x+\lambda=0\) to have real and distinct roots, which condition is correct?
Explanation opens after your attempt
Correct Answer
A. \(\lambda<\frac{9}{8}\)
Concept
(D=32-4(2)\lambda=9-8\lambda). From (D>0), we get \(\lambda<\frac{9}{8}\).
Why this answer is correct
The correct answer is A. \(\lambda<\frac{9}{8}\). (D=32-4(2)\lambda=9-8\lambda). From (D>0), we get \(\lambda<\frac{9}{8}\).
Exam Tip
(D=32-4(2)\lambda=9-8\lambda) है। (D>0) से \(\lambda<\frac{9}{8}\) मिलता है।
Login to save your score, XP, coins and progress.