युग्म (8x+ay=12) और (20x+10y=30) के अनंत हलों के लिए (a) का मान बताइए।

Find the value of (a) for infinitely many solutions of (8x+ay=12) and (20x+10y=30).

Explanation opens after your attempt
Correct Answer

B. (a=4)

Step 1

Concept

Here \(\frac{8}{20}=\frac{12}{30}\). Thus \(\frac{a}{10}=\frac{2}{5}\) gives (a=4).

Step 2

Why this answer is correct

The correct answer is B. (a=4). Here \(\frac{8}{20}=\frac{12}{30}\). Thus \(\frac{a}{10}=\frac{2}{5}\) gives (a=4).

Step 3

Exam Tip

यहाँ \(\frac{8}{20}=\frac{12}{30}\) है। अतः \(\frac{a}{10}=\frac{2}{5}\) से (a=4) होगा।

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Mathematics Answer, Explanation and Revision Hints

युग्म (8x+ay=12) और (20x+10y=30) के अनंत हलों के लिए (a) का मान बताइए। / Find the value of (a) for infinitely many solutions of (8x+ay=12) and (20x+10y=30).

Correct Answer: B. (a=4). Explanation: यहाँ \(\frac{8}{20}=\frac{12}{30}\) है। अतः \(\frac{a}{10}=\frac{2}{5}\) से (a=4) होगा। / Here \(\frac{8}{20}=\frac{12}{30}\). Thus \(\frac{a}{10}=\frac{2}{5}\) gives (a=4).

Which concept should I revise for this Mathematics MCQ?

Here \(\frac{8}{20}=\frac{12}{30}\). Thus \(\frac{a}{10}=\frac{2}{5}\) gives (a=4).

What exam hint can help solve this Mathematics question?

यहाँ \(\frac{8}{20}=\frac{12}{30}\) है। अतः \(\frac{a}{10}=\frac{2}{5}\) से (a=4) होगा।

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