व्यंजक \(x+\sqrt[3]{x}\) बहुपद क्यों नहीं है?

Why is \(x+\sqrt[3]{x}\) not a polynomial?

Explanation opens after your attempt
Correct Answer

D. क्योंकि \(\sqrt[3]{x}=x^{\frac{1}{3}}\) हैBecause \(\sqrt[3]{x}=x^{\frac{1}{3}}\)

Step 1

Concept

The power of \(\sqrt[3]{x}\) is \(\frac{1}{3}\). Fractional powers are not valid in a polynomial.

Step 2

Why this answer is correct

The correct answer is D. क्योंकि \(\sqrt[3]{x}=x^{\frac{1}{3}}\) है / Because \(\sqrt[3]{x}=x^{\frac{1}{3}}\). The power of \(\sqrt[3]{x}\) is \(\frac{1}{3}\). Fractional powers are not valid in a polynomial.

Step 3

Exam Tip

\(\sqrt[3]{x}\) में चर की घात \(\frac{1}{3}\) है। भिन्न घात बहुपद में मान्य नहीं होती।

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FAQs

Mathematics Answer, Explanation and Revision Hints

व्यंजक \(x+\sqrt[3]{x}\) बहुपद क्यों नहीं है? / Why is \(x+\sqrt[3]{x}\) not a polynomial?

Correct Answer: D. क्योंकि \(\sqrt[3]{x}=x^{\frac{1}{3}}\) है / Because \(\sqrt[3]{x}=x^{\frac{1}{3}}\). Explanation: \(\sqrt[3]{x}\) में चर की घात \(\frac{1}{3}\) है। भिन्न घात बहुपद में मान्य नहीं होती। / The power of \(\sqrt[3]{x}\) is \(\frac{1}{3}\). Fractional powers are not valid in a polynomial.

Which concept should I revise for this Mathematics MCQ?

The power of \(\sqrt[3]{x}\) is \(\frac{1}{3}\). Fractional powers are not valid in a polynomial.

What exam hint can help solve this Mathematics question?

\(\sqrt[3]{x}\) में चर की घात \(\frac{1}{3}\) है। भिन्न घात बहुपद में मान्य नहीं होती।