व्यंजक \(x^{\frac{1}{2}}+9\) बहुपद क्यों नहीं है?
Why is \(x^{\frac{1}{2}}+9\) not a polynomial?
Explanation opens after your attempt
Correct Answer
B. क्योंकि चर की घात भिन्न हैBecause the variable has a fractional power
Concept
In \(x^{\frac{1}{2}}\), the power is fractional. In a polynomial, the variable power must be a non-negative integer.
Why this answer is correct
The correct answer is B. क्योंकि चर की घात भिन्न है / Because the variable has a fractional power. In \(x^{\frac{1}{2}}\), the power is fractional. In a polynomial, the variable power must be a non-negative integer.
Exam Tip
\(x^{\frac{1}{2}}\) में घात भिन्न है। बहुपद में चर की घात अऋणात्मक पूर्णांक होनी चाहिए।
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