व्यंजक \(x^3+\frac{1}{x^2}\) बहुपद क्यों नहीं है?
Why is \(x^3+\frac{1}{x^2}\) not a polynomial?
Explanation opens after your attempt
Correct Answer
D. क्योंकि \(\frac{1}{x^2}=x^{-2}\) हैBecause \(\frac{1}{x^2}=x^{-2}\)
Concept
In \(\frac{1}{x^2}\), the variable has power (-2). A polynomial cannot have a negative power.
Why this answer is correct
The correct answer is D. क्योंकि \(\frac{1}{x^2}=x^{-2}\) है / Because \(\frac{1}{x^2}=x^{-2}\). In \(\frac{1}{x^2}\), the variable has power (-2). A polynomial cannot have a negative power.
Exam Tip
\(\frac{1}{x^2}\) में चर की घात (-2) है। बहुपद में ऋणात्मक घात नहीं होती।
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