व्यंजक \(x^2+\sqrt[3]{x}\) बहुपद क्यों नहीं है?
Why is \(x^2+\sqrt[3]{x}\) not a polynomial?
Explanation opens after your attempt
Correct Answer
A. क्योंकि \(\sqrt[3]{x}=x^{\frac{1}{3}}\) हैBecause \(\sqrt[3]{x}=x^{\frac{1}{3}}\)
Concept
The power of \(\sqrt[3]{x}\) is \(\frac{1}{3}\). An expression with a fractional power is not a polynomial.
Why this answer is correct
The correct answer is A. क्योंकि \(\sqrt[3]{x}=x^{\frac{1}{3}}\) है / Because \(\sqrt[3]{x}=x^{\frac{1}{3}}\). The power of \(\sqrt[3]{x}\) is \(\frac{1}{3}\). An expression with a fractional power is not a polynomial.
Exam Tip
\(\sqrt[3]{x}\) की घात \(\frac{1}{3}\) है। भिन्न घात होने पर व्यंजक बहुपद नहीं होता।
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