व्यंजक \(x^2+\frac{1}{x}\) बहुपद क्यों नहीं है?
Why is \(x^2+\frac{1}{x}\) not a polynomial?
Explanation opens after your attempt
Correct Answer
B. क्योंकि \(\frac{1}{x}=x^{-1}\) हैBecause \(\frac{1}{x}=x^{-1}\)
Concept
In \(\frac{1}{x}\), the power of (x) is (-1). Negative powers are not valid in a polynomial.
Why this answer is correct
The correct answer is B. क्योंकि \(\frac{1}{x}=x^{-1}\) है / Because \(\frac{1}{x}=x^{-1}\). In \(\frac{1}{x}\), the power of (x) is (-1). Negative powers are not valid in a polynomial.
Exam Tip
\(\frac{1}{x}\) में (x) की घात (-1) है। बहुपद में ऋणात्मक घात मान्य नहीं होती।
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