व्यंजक \(x^2+\frac{1}{x^3}\) बहुपद क्यों नहीं है?

Why is \(x^2+\frac{1}{x^3}\) not a polynomial?

Explanation opens after your attempt
Correct Answer

B. क्योंकि \(\frac{1}{x^3}=x^{-3}\) हैBecause \(\frac{1}{x^3}=x^{-3}\)

Step 1

Concept

In \(\frac{1}{x^3}\), the variable has power (-3). Negative powers are not valid in a polynomial.

Step 2

Why this answer is correct

The correct answer is B. क्योंकि \(\frac{1}{x^3}=x^{-3}\) है / Because \(\frac{1}{x^3}=x^{-3}\). In \(\frac{1}{x^3}\), the variable has power (-3). Negative powers are not valid in a polynomial.

Step 3

Exam Tip

\(\frac{1}{x^3}\) में चर की घात (-3) है। बहुपद में ऋणात्मक घात मान्य नहीं होती।

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Mathematics Answer, Explanation and Revision Hints

व्यंजक \(x^2+\frac{1}{x^3}\) बहुपद क्यों नहीं है? / Why is \(x^2+\frac{1}{x^3}\) not a polynomial?

Correct Answer: B. क्योंकि \(\frac{1}{x^3}=x^{-3}\) है / Because \(\frac{1}{x^3}=x^{-3}\). Explanation: \(\frac{1}{x^3}\) में चर की घात (-3) है। बहुपद में ऋणात्मक घात मान्य नहीं होती। / In \(\frac{1}{x^3}\), the variable has power (-3). Negative powers are not valid in a polynomial.

Which concept should I revise for this Mathematics MCQ?

In \(\frac{1}{x^3}\), the variable has power (-3). Negative powers are not valid in a polynomial.

What exam hint can help solve this Mathematics question?

\(\frac{1}{x^3}\) में चर की घात (-3) है। बहुपद में ऋणात्मक घात मान्य नहीं होती।