व्यंजक \(\frac{x^3+1}{x}\) बहुपद क्यों नहीं है?
Why is \(\frac{x^3+1}{x}\) not a polynomial?
Explanation opens after your attempt
Correct Answer
A. क्योंकि सरल करने पर \(x^2+\frac{1}{x}\) मिलता हैBecause simplifying gives \(x^2+\frac{1}{x}\)
Concept
\(\frac{x^3+1}{x}=x^2+\frac{1}{x}\). In \(\frac{1}{x}\), the power of (x) is (-1).
Why this answer is correct
The correct answer is A. क्योंकि सरल करने पर \(x^2+\frac{1}{x}\) मिलता है / Because simplifying gives \(x^2+\frac{1}{x}\). \(\frac{x^3+1}{x}=x^2+\frac{1}{x}\). In \(\frac{1}{x}\), the power of (x) is (-1).
Exam Tip
\(\frac{x^3+1}{x}=x^2+\frac{1}{x}\) है। \(\frac{1}{x}\) में (x) की घात (-1) है।
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