कौन-सा कथन \(x^2+\sqrt{x}+1\) के बारे में सही है?
Which statement is correct about \(x^2+\sqrt{x}+1\)?
Explanation opens after your attempt
B. यह बहुपद नहीं है क्योंकि (\sqrt{x}=x^{12}) है / It is not a polynomial because \(\sqrt{x}=x^{1 / 2}\)
Concept
In a polynomial, powers of the variable must be integers. \(\frac{1}{2}\) is not an integer.
Why this answer is correct
The correct answer is B. यह बहुपद नहीं है क्योंकि \(\sqrt{x}=x^{1 / 2}\) है / It is not a polynomial because \(\sqrt{x}=x^{1 / 2}\). In a polynomial, powers of the variable must be integers. \(\frac{1}{2}\) is not an integer.
Exam Tip
बहुपद में चर की घातें पूर्णांक होनी चाहिए। \(\frac{1}{2}\) पूर्णांक नहीं है।
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