वर्गमूल सर्पिल में \(\sqrt{4}\) तक पहुँचने के लिए कौन-सा क्रम सही है?

Which sequence is correct to reach \(\sqrt{4}\) in a square root spiral?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(\sqrt{1}\rightarrow\sqrt{2}\rightarrow\sqrt{3}\rightarrow\sqrt{4}\)

Step 1

Concept

In a square root spiral, hypotenuses are formed in order. In the usual construction, the \(\sqrt{3}\) step is not skipped.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{1}\rightarrow\sqrt{2}\rightarrow\sqrt{3}\rightarrow\sqrt{4}\). In a square root spiral, hypotenuses are formed in order. In the usual construction, the \(\sqrt{3}\) step is not skipped.

Step 3

Exam Tip

वर्गमूल सर्पिल में कर्ण क्रम से बनते हैं। सामान्य निर्माण में \(\sqrt{3}\) चरण छोड़ा नहीं जाता।

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वर्गमूल सर्पिल में \(\sqrt{4}\) तक पहुँचने के लिए कौन-सा क्रम सही है? / Which sequence is correct to reach \(\sqrt{4}\) in a square root spiral?

Correct Answer: B. \(\sqrt{1}\rightarrow\sqrt{2}\rightarrow\sqrt{3}\rightarrow\sqrt{4}\). Explanation: वर्गमूल सर्पिल में कर्ण क्रम से बनते हैं। सामान्य निर्माण में \(\sqrt{3}\) चरण छोड़ा नहीं जाता। / In a square root spiral, hypotenuses are formed in order. In the usual construction, the \(\sqrt{3}\) step is not skipped.

Which concept should I revise for this Mathematics MCQ?

In a square root spiral, hypotenuses are formed in order. In the usual construction, the \(\sqrt{3}\) step is not skipped.

What exam hint can help solve this Mathematics question?

वर्गमूल सर्पिल में कर्ण क्रम से बनते हैं। सामान्य निर्माण में \(\sqrt{3}\) चरण छोड़ा नहीं जाता।