वर्गमूल सर्पिल में \(\sqrt{224}\) बनाने के लिए कौन-सा पिछला कर्ण सही है?
Which previous hypotenuse is correct for constructing \(\sqrt{224}\) in a square root spiral?
Explanation opens after your attempt
B. \(\sqrt{223}\)
Concept
Adding a (1) unit perpendicular to \(\sqrt{223}\) forms \(\sqrt{224}\). The number increases by (1) in the next hypotenuse.
Why this answer is correct
The correct answer is B. \(\sqrt{223}\). Adding a (1) unit perpendicular to \(\sqrt{223}\) forms \(\sqrt{224}\). The number increases by (1) in the next hypotenuse.
Exam Tip
\(\sqrt{223}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{224}\) बनता है। अगले कर्ण में संख्या (1) बढ़ती है।
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