वर्गमूल सर्पिल में \(\sqrt{224}\) बनाने के लिए कौन-सा पिछला कर्ण सही है?

Which previous hypotenuse is correct for constructing \(\sqrt{224}\) in a square root spiral?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(\sqrt{223}\)

Step 1

Concept

Adding a (1) unit perpendicular to \(\sqrt{223}\) forms \(\sqrt{224}\). The number increases by (1) in the next hypotenuse.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{223}\). Adding a (1) unit perpendicular to \(\sqrt{223}\) forms \(\sqrt{224}\). The number increases by (1) in the next hypotenuse.

Step 3

Exam Tip

\(\sqrt{223}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{224}\) बनता है। अगले कर्ण में संख्या (1) बढ़ती है।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{224}\) बनाने के लिए कौन-सा पिछला कर्ण सही है? / Which previous hypotenuse is correct for constructing \(\sqrt{224}\) in a square root spiral?

Correct Answer: B. \(\sqrt{223}\). Explanation: \(\sqrt{223}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{224}\) बनता है। अगले कर्ण में संख्या (1) बढ़ती है। / Adding a (1) unit perpendicular to \(\sqrt{223}\) forms \(\sqrt{224}\). The number increases by (1) in the next hypotenuse.

Which concept should I revise for this Mathematics MCQ?

Adding a (1) unit perpendicular to \(\sqrt{223}\) forms \(\sqrt{224}\). The number increases by (1) in the next hypotenuse.

What exam hint can help solve this Mathematics question?

\(\sqrt{223}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{224}\) बनता है। अगले कर्ण में संख्या (1) बढ़ती है।