किस विकल्प में (x) में बहुपद नहीं है, लेकिन \(x^2\) पद मौजूद है?
Which option is not a polynomial in (x), even though an \(x^2\) term is present?
Explanation opens after your attempt
Correct Answer
B. \(x^2+\sqrt{x}+4\)
Concept
Having an \(x^2\) term is not enough. \(\sqrt{x}=x^{1/2}\) is a term with an invalid power.
Why this answer is correct
The correct answer is B. \(x^2+\sqrt{x}+4\). Having an \(x^2\) term is not enough. \(\sqrt{x}=x^{1/2}\) is a term with an invalid power.
Exam Tip
\(x^2\) पद होना पर्याप्त नहीं है। \(\sqrt{x}=x^{1/2}\) अमान्य घात वाला पद है।
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