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Which option is not a polynomial in its original form because the variable is in the denominator?

Answer and explanation

Correct answer: (x² + 4)/(x + 1)

Option B is correct. In the original form (x² + 4)/(x + 1), the variable x occurs in the denominator. Equivalently, the expression involves division by a variable-containing quantity, so it cannot be written as a finite sum of terms with only non-negative integer powers of x and constant coefficients. The denominator also creates a restriction x ≠ -1. Options A and D are ordinary polynomials with non-negative integer powers. Option C is also a polynomial because √2 is merely a constant coefficient of x²; irrational coefficients are allowed. The phrase “in its original form” matters: a rational expression may simplify in special cases, but it must be classified as written. Therefore B is the only valid answer.

Related tags

PolynomialVariable-DenominatorNon-PolynomialDefinition Of A PolynomialIntroduction To PolynomialsMathematicsClass 9 Mcq

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