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Which option is a complete group of like terms of (a^2b)?

Answer and explanation

Correct answer: (3a^2b), (-5a^2b), (8a^2b)

The direct answer is option A. Like terms must have exactly the same variables raised to exactly the same powers. Numerical coefficients may differ, but the variable part must match. In option A, \(3a^2b\), \(-5a^2b\), and \(8a^2b\) all have the variable part \(a^2b\), so they form a complete group of like terms. Option B contains \(a^2b\), \(ab^2\), and \(a^2\); the powers or variables differ, so they are not all alike. Option C contains \(2ab\), \(4a^2b\), and \(6ab^2\); again, the exponents do not match. Option D contains \(a^2b\), \(a^3b\), and \(a^2b^2\), which also have different powers. Option A is correct even though one coefficient is negative, because the sign and coefficient may change while the literal part remains identical. Exam cue: compare letters and exponents, not coefficients.

Related tags

Algebraic-ExpressionsLike-TermsClassification

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