Which option contains the first three terms formed by (a_n=3n^2-2n+6)?
Answer and explanation
Correct answer: (7, 14, 27)
Substituting n=1, 2, and 3 into the rule gives a_1=3(1)^2-2(1)+6=7, a_2=3(2)^2-2(2)+6=14, and a_3=3(3)^2-2(3)+6=27. Hence, the correct sequence is (7, 14, 27). Option D has the correct first term, but for n=2 the value is 14, not 16. Exam tip: substitute each value of n carefully into the entire expression.
Frequently asked questions
What is the correct answer to this question?
(7, 14, 27)
Why is this the correct answer?
Substituting n=1, 2, and 3 into the rule gives a_1=3(1)^2-2(1)+6=7, a_2=3(2)^2-2(2)+6=14, and a_3=3(3)^2-2(3)+6=27. Hence, the correct sequence is (7, 14, 27). Option D has the correct first term, but for n=2 the value is 14, not 16. Exam tip: substitute each value of n carefully into the entire expression.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Explicit or general rule.
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