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Which of the following expressions is factorised using the identity for the difference of squares?

Answer and explanation

Correct answer: \(p^2-q^2\)

Correct answer: A. The difference-of-squares identity is \(a^2-b^2=(a-b)(a+b)\). Option A has exactly two square terms, \(p^2\) and \(q^2\), separated by a minus sign. Therefore, \(p^2-q^2=(p-q)(p+q)\). B has a plus sign, so it is a sum of squares and does not match this identity. C matches \(p^2+2pq+q^2=(p+q)^2\), the square of a sum. D matches \(p^2-2pq+q^2=(p-q)^2\), the square of a difference. The middle terms in C and D are important clues that those are trinomials, not two-term differences. Memory cue: ‘minus between two squares’ means difference of squares; ‘minus twice the product’ means a square of a difference.

Related tags

FactorisationAlgebraic IdentitiesDifference Of SquaresPerfect Square TrinomialsClass 9 MathematicsExploring Algebraic IdentitiesMathematicsClass 9 Mcq

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