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Which is the correct rule for the sequence (\frac{3}{7},\frac{6}{12},\frac{9}{17},\frac{12}{22},\ldots)?

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Answer and explanation

Correct answer: (a_n=\frac{3n}{5n+2})

The rule of a sequence can be found by observing how the numerator and denominator depend on n. The numerators are 3, 6, 9, and 12, which are exactly 3n for n=1, 2, 3, and 4. The denominators are 7, 12, 17, and 22. They increase by 5, and the expression 5n+2 gives these values. Thus the general term is \(a_n=\frac{3n}{5n+2}\), which is option A.

Substitution verifies the answer: at n=1, \(\frac{3}{7}\) is obtained; at n=2, \(\frac{6}{12}\); at n=3, \(\frac{9}{17}\); and at n=4, \(\frac{12}{22}\). Option C uses the wrong denominator pattern, and options B and D do not produce the numerators 3n. Both parts of the fraction must match the sequence.

Related tags

SequencesProgressionsFraction-SequenceGeneral-Rule

Frequently asked questions

What is the correct answer to this question?

(a_n=\frac{3n}{5n+2})

Why is this the correct answer?

The rule of a sequence can be found by observing how the numerator and denominator depend on n. The numerators are 3, 6, 9, and 12, which are exactly 3n for n=1, 2, 3, and 4. The denominators are 7, 12, 17, and 22. They increase by 5, and the expression 5n+2 gives these values. Thus the general term is \(a_n=\frac{3n}{5n+2}\), which is option A.

Substitution verifies the answer: at n=1, \(\frac{3}{7}\) is obtained; at n=2, \(\frac{6}{12}\); at n=3, \(\frac{9}{17}\); and at n=4, \(\frac{12}{22}\). Option C uses the wrong denominator pattern, and options B and D do not produce the numerators 3n. Both parts of the fraction must match the sequence.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Explicit or general rule.

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