\(a^4-16b^4\) का पूर्ण गुणनखंड रूप कौन सा है?

Which is the complete factorised form of \(a^4-16b^4\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. ((a-2b)(a+2b)\(a^2+4b^2\))

Step 1

Concept

First (a-4-16b-4=\(a^2-4b^2\)\(a^2+4b^2\)), then \(a^2-4b^2\) factors further. Exam tip: stop only after complete factorisation.

Step 2

Why this answer is correct

The correct answer is B. ((a-2b)(a+2b)\(a^2+4b^2\)). First (a-4-16b-4=\(a^2-4b^2\)\(a^2+4b^2\)), then \(a^2-4b^2\) factors further. Exam tip: stop only after complete factorisation.

Step 3

Exam Tip

पहले (a-4-16b-4=\(a^2-4b^2\)\(a^2+4b^2\)), फिर \(a^2-4b^2\) टूटता है। परीक्षा में पूर्ण गुणनखंड तक रुकें।

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Mathematics Answer, Explanation and Revision Hints

\(a^4-16b^4\) का पूर्ण गुणनखंड रूप कौन सा है? / Which is the complete factorised form of \(a^4-16b^4\)?

Correct Answer: B. ((a-2b)(a+2b)\(a^2+4b^2\)). Explanation: पहले (a-4-16b-4=\(a^2-4b^2\)\(a^2+4b^2\)), फिर \(a^2-4b^2\) टूटता है। परीक्षा में पूर्ण गुणनखंड तक रुकें। / First (a-4-16b-4=\(a^2-4b^2\)\(a^2+4b^2\)), then \(a^2-4b^2\) factors further. Exam tip: stop only after complete factorisation.

Which concept should I revise for this Mathematics MCQ?

First (a-4-16b-4=\(a^2-4b^2\)\(a^2+4b^2\)), then \(a^2-4b^2\) factors further. Exam tip: stop only after complete factorisation.

What exam hint can help solve this Mathematics question?

पहले (a-4-16b-4=\(a^2-4b^2\)\(a^2+4b^2\)), फिर \(a^2-4b^2\) टूटता है। परीक्षा में पूर्ण गुणनखंड तक रुकें।